Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation cos(pi*x)=0
- Equation x^(log(x,1/3)+4)=1/243
- Equation 3×(x+5)=5×(12-x)-5
- Equation (3-2sqrt(2))^x+(3+2sqrt(2))^x=6^x
- Express {x} in terms of y where:
- sqrt(x^2+y^2+4x-6y-12)+(x^2+10x-27)=8-|y-9|+|y-3|
- -1*x-19*y=-10
- (x^2+y^2-1)^3+x^2*y^3=0
- 4*x-16*y=6
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Identical expressions
- three ×(x+ five)= five ×(twelve -x)- five
- 3×(x plus 5) equally 5×(12 minus x) minus 5
- three ×(x plus five) equally five ×(twelve minus x) minus five
- 3×x+5=5×12-x-5
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Similar expressions
- 3×x+50=70
- (3×x+5)÷12-2=(x+5)÷9-(x÷6)
- 3×(x+5)=5×(12+x)-5
- 3×(x-5)=5×(12-x)-5
- 3×(x+5)=5×(12-x)+5
3×(x+5)=5×(12-x)-5 equation
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The solution
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3*(x + 5) = 5*(12 - x) - 5
$$3 \left(x + 5\right) = 5 \left(12 - x\right) - 5$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$3 x = 40 - 5 x$$
Move the summands with the unknown x
from the right part to the left part:
$$8 x = 40$$
Divide both parts of the equation by 8
We get the answer: x = 5
3*(x+5) = 5*(12-x)-5
Expand brackets in the left part
3*x+3*5 = 5*(12-x)-5
Expand brackets in the right part
3*x+3*5 = 5*12-5*x-5
Looking for similar summands in the right part:
15 + 3*x = 55 - 5*x
Move free summands (without x)
from left part to right part, we given:
$$3 x = 40 - 5 x$$
Move the summands with the unknown x
from the right part to the left part:
$$8 x = 40$$
Divide both parts of the equation by 8
x = 40 / (8)
We get the answer: x = 5