Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^3=3
-
Equation 5-x^2=0
- Equation (-5*x+3)*(-x+8)=0
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Equation 5x^2+9x+4=0
- Express {x} in terms of y where:
- -6*x+11*y=-5
- -3*x-19*y=-9
- 16*x+14*y=-14
- 3*x-14*y=-2
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Identical expressions
- (three x- one)*(2x- three)=(6x- five)*(x-3)+ four
- (3x minus 1) multiply by (2x minus 3) equally (6x minus 5) multiply by (x minus 3) plus 4
- (three x minus one) multiply by (2x minus three) equally (6x minus five) multiply by (x minus 3) plus four
- (3x-1)(2x-3)=(6x-5)(x-3)+4
- 3x-12x-3=6x-5x-3+4
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Similar expressions
- (3x-1)(2x-3)-(6x-5)(x-2)+4=0
- (3x-1)*(2x-3)=(6x+5)*(x-3)+4
- (3x-1)*(2x-3)=(6x-5)*(x-3)-4
- (3x+1)*(2x-3)=(6x-5)*(x-3)+4
- (3x-1)*(2x+3)=(6x-5)*(x-3)+4
- (3x-1)*(2x-3)=(6x-5)*(x+3)+4
(3x-1)*(2x-3)=(6x-5)*(x-3)+4 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
(3*x - 1)*(2*x - 3) = (6*x - 5)*(x - 3) + 4
$$\left(2 x - 3\right) \left(3 x - 1\right) = \left(x - 3\right) \left(6 x - 5\right) + 4$$
Detail solution
Given the equation:
Expand expressions:
Reducing, you get:
Move free summands (without x)
from left part to right part, we given:
$$12 x = 16$$
Divide both parts of the equation by 12
We get the answer: x = 4/3
(3*x-1)*(2*x-3) = (6*x-5)*(x-3)+4
Expand expressions:
3 - 11*x + 6*x^2 = (6*x-5)*(x-3)+4
(3*x-1)*(2*x-3) = 15 - 23*x + 6*x^2 + 4
Reducing, you get:
-16 + 12*x = 0
Move free summands (without x)
from left part to right part, we given:
$$12 x = 16$$
Divide both parts of the equation by 12
x = 16 / (12)
We get the answer: x = 4/3
Sum and product of roots
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sum
4/3
$$\frac{4}{3}$$
=
4/3
$$\frac{4}{3}$$
product
4/3
$$\frac{4}{3}$$
=
4/3
$$\frac{4}{3}$$
4/3