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- Equation:
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Equation log(4/(7-x))/log(x^2)=5
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Equation sin(x+pi/3)=0
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Equation (7x+9)-(11x-7)=8
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Equation 13/(x-5)=5/(x-13)
- Express {x} in terms of y where:
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Identical expressions
- thirteen /(x- five)= five /(x- thirteen)
- 13 divide by (x minus 5) equally 5 divide by (x minus 13)
- thirteen divide by (x minus five) equally five divide by (x minus thirteen)
- 13/x-5=5/x-13
- 13 divide by (x-5)=5 divide by (x-13)
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Similar expressions
- 13/(x-5)=5/(x+13)
- (13)/(x-5)=(5)/(x-13)
- 13/(x+5)=5/(x-13)
- ((6x-14)/((x-1)^2))-((2(3x^2-14x-5))/((x-1)^3))=0
13/(x-5)=5/(x-13) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{13}{x - 5} = \frac{5}{x - 13}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
so we get the equation
$$13 \left(x - 13\right) = 5 \left(x - 5\right)$$
$$13 x - 169 = 5 x - 25$$
Move free summands (without x)
from left part to right part, we given:
$$13 x = 5 x + 144$$
Move the summands with the unknown x
from the right part to the left part:
$$8 x = 144$$
Divide both parts of the equation by 8
We get the answer: x = 18
$$\frac{13}{x - 5} = \frac{5}{x - 13}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
a1 = 13
b1 = -5 + x
a2 = 5
b2 = -13 + x
so we get the equation
$$13 \left(x - 13\right) = 5 \left(x - 5\right)$$
$$13 x - 169 = 5 x - 25$$
Move free summands (without x)
from left part to right part, we given:
$$13 x = 5 x + 144$$
Move the summands with the unknown x
from the right part to the left part:
$$8 x = 144$$
Divide both parts of the equation by 8
x = 144 / (8)
We get the answer: x = 18
The graph