Mister Exam
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How to use it?
- Equation:
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Equation 4(x-1)(x-7)=3x^2-16x
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Equation 2tgx–9ctgx+3=0
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Equation sqrt(((3)/20-5x))=0,2
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Equation 18-7x=10-3(x+4)
- Express {x} in terms of y where:
- 9*x+18*y=6
- 15*x-15*y=16
- sqrt(x^2+y^2+4x-6y-12)+(x^2+10x-27)=8-|y-9|+|y-3|
- (x^2+y^2-1)^3+x^2*y^3=0
- Sum of series:
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0,2
- Integral of d{x}:
- 0,2
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Identical expressions
- sqrt(((three)/ twenty -5x))= zero , two
- square root of (((3) divide by 20 minus 5x)) equally 0,2
- square root of (((three) divide by twenty minus 5x)) equally zero , two
- √(((3)/20-5x))=0,2
- sqrt3/20-5x=0,2
- sqrt(((3)/20-5x))=O,2
- sqrt(((3) divide by 20-5x))=0,2
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Similar expressions
- sqrt(((3)/20+5x))=0,2
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What you mean?
- sqrt(3/(20 - 5*x)) = 1/5
- sqrt(3*x/(20 - 1*5)) = 1/5
- sqrt(-5*x + 3/20) = 1/5
- sqrt(-5*x + 3/20) = 1/5
You entered:
sqrt(((3)/20-5x))=0,2
What you mean?
sqrt(((3)/20-5x))=0,2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
__________ / 3 / -- - 5*x = 1/5 \/ 20
$$\sqrt{- 5 x + \frac{3}{20}} = \frac{1}{5}$$
Detail solution
Given the equation
$$\sqrt{- 5 x + \frac{3}{20}} = \frac{1}{5}$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{- 5 x + \frac{3}{20}}\right)^{2} = \left(\frac{1}{5}\right)^{2}$$
or
$$- 5 x + \frac{3}{20} = \frac{1}{25}$$
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = - \frac{11}{100}$$
Divide both parts of the equation by -5
We get the answer: x = 11/500
The final answer:
$$x_{1} = \frac{11}{500}$$
$$\sqrt{- 5 x + \frac{3}{20}} = \frac{1}{5}$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{- 5 x + \frac{3}{20}}\right)^{2} = \left(\frac{1}{5}\right)^{2}$$
or
$$- 5 x + \frac{3}{20} = \frac{1}{25}$$
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = - \frac{11}{100}$$
Divide both parts of the equation by -5
x = -11/100 / (-5)
We get the answer: x = 11/500
The final answer:
$$x_{1} = \frac{11}{500}$$
Sum and product of roots
[src]
sum
11 --- 500
$$\left(\frac{11}{500}\right)$$
=
11 --- 500
$$\frac{11}{500}$$
product
11 --- 500
$$\left(\frac{11}{500}\right)$$
=
11 --- 500
$$\frac{11}{500}$$
The graph