sqrt(6*x-8)=sqrt(3*x+3) equation
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The solution
Detail solution
Given the equation
$$\sqrt{6 x - 8} = \sqrt{3 x + 3}$$
We raise the equation sides to 2-th degree
$$6 x - 8 = 3 x + 3$$
Move free summands (without x)
from left part to right part, we given:
$$6 x = 3 x + 11$$
Move the summands with the unknown x
from the right part to the left part:
$$3 x = 11$$
Divide both parts of the equation by 3
x = 11 / (3)
We get the answer: x = 11/3
check:
$$x_{1} = \frac{11}{3}$$
$$- \sqrt{3 x_{1} + 3} + \sqrt{6 x_{1} - 8} = 0$$
=
$$- \sqrt{3 + \frac{3 \cdot 11}{3}} + \sqrt{-8 + \frac{6 \cdot 11}{3}} = 0$$
=
0 = 0
- the identity
The final answer:
$$x_{1} = \frac{11}{3}$$
Sum and product of roots
[src]
$$\frac{11}{3}$$
$$\frac{11}{3}$$
$$\frac{11}{3}$$
$$\frac{11}{3}$$