sqrt(3x+34)=8 equation
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The solution
Detail solution
Given the equation
$$\sqrt{3 x + 34} = 8$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{3 x + 34}\right)^{2} = 8^{2}$$
or
$$3 x + 34 = 64$$
Move free summands (without x)
from left part to right part, we given:
$$3 x = 30$$
Divide both parts of the equation by 3
x = 30 / (3)
We get the answer: x = 10
The final answer:
$$x_{1} = 10$$
Sum and product of roots
[src]
$$0 + 10$$
$$10$$
$$1 \cdot 10$$
$$10$$