Given the equation −17x−72=−x −17x−72=−x We raise the equation sides to 2-th degree −17x−72=x2 −17x−72=x2 Transfer the right side of the equation left part with negative sign −x2−17x−72=0 This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved using the discriminant. The roots of the quadratic equation: x1=2aD−b x2=2a−D−b where D = b^2 - 4*a*c - it is the discriminant. Because a=−1 b=−17 c=−72 , then
D = b^2 - 4 * a * c =
(-17)^2 - 4 * (-1) * (-72) = 1
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or x1=−9 x2=−8
Because −17x−72=−x and −17x−72≥0 then −x≥0 or x≤0 −∞<x The final answer: x1=−9 x2=−8