6-2*x=3*x-10 equation
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The solution
Detail solution
Given the linear equation:
6-2*x = 3*x-10
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = 3 x - 16$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-5\right) x = -16$$
Divide both parts of the equation by -5
x = -16 / (-5)
We get the answer: x = 16/5
Sum and product of roots
[src]
$$\frac{16}{5}$$
$$\frac{16}{5}$$
$$\frac{16}{5}$$
$$\frac{16}{5}$$