Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- -16*x-10*y=4
- 12*x-20*y=9
- -3*x-10*y=1
- 11*x-6*y=5
- Equation:
-
Equation x^3+4*x^2-9*x-36=0
-
Equation 16*x^3+8*x^2+x=0
-
Equation x^2-6=0
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Equation (x+4)(x-2)=x(2-3x)
- Integral of d{x}:
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12
- Derivative of:
- 12
- Canonical form:
- 12
-
Identical expressions
- - fifteen *x- five *y= twelve
- minus 15 multiply by x minus 5 multiply by y equally 12
- minus fifteen multiply by x minus five multiply by y equally twelve
- -15x-5y=12
-
Similar expressions
- -15*x+5*y=12
- 15*x-5*y=12
Express x in terms of y where -15*x-5*y=12
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 15 x = 5 y + 12$$
Divide both parts of the equation by -15
We get the answer: x = -4/5 - y/3
-15*x-5*y = 12
Looking for similar summands in the left part:
-15*x - 5*y = 12
Move the summands with the other variables
from left part to right part, we given:
$$- 15 x = 5 y + 12$$
Divide both parts of the equation by -15
x = 12 + 5*y / (-15)
We get the answer: x = -4/5 - y/3
Rapid solution
[src]
4 re(y) I*im(y)
x1 = - - - ----- - -------
5 3 3
$$x_{1} = - \frac{\operatorname{re}{\left(y\right)}}{3} - \frac{i \operatorname{im}{\left(y\right)}}{3} - \frac{4}{5}$$
x1 = -re(y)/3 - i*im(y)/3 - 4/5