Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 5(x-4)=3x-10
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Equation |x|=-1
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Equation tan(x)=7
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Equation 6-3*(x+1)=7-2*x
- Express {x} in terms of y where:
- 13*x-1*y=-4
- -17*x+6*y=14
- -15*x-5*y=12
- -1*x+11*y=-9
- Derivative of:
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|x|
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-1
- Integral of d{x}:
- |x|
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-1
- Limit of the function:
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|x|
- Sum of series:
-
-1
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Identical expressions
- |x|=- one
- module of x| equally minus 1
- module of x| equally minus one
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Similar expressions
- |x|=+1
|x|=-1 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x \geq 0$$
or
$$0 \leq x \wedge x < \infty$$
we get the equation
$$x + 1 = 0$$
after simplifying we get
$$x + 1 = 0$$
the solution in this interval:
$$x_{1} = -1$$
but x1 not in the inequality interval
2.
$$x < 0$$
or
$$-\infty < x \wedge x < 0$$
we get the equation
$$1 - x = 0$$
after simplifying we get
$$1 - x = 0$$
the solution in this interval:
$$x_{2} = 1$$
but x2 not in the inequality interval
The final answer:
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x \geq 0$$
or
$$0 \leq x \wedge x < \infty$$
we get the equation
$$x + 1 = 0$$
after simplifying we get
$$x + 1 = 0$$
the solution in this interval:
$$x_{1} = -1$$
but x1 not in the inequality interval
2.
$$x < 0$$
or
$$-\infty < x \wedge x < 0$$
we get the equation
$$1 - x = 0$$
after simplifying we get
$$1 - x = 0$$
the solution in this interval:
$$x_{2} = 1$$
but x2 not in the inequality interval
The final answer:
The graph