Mister Exam
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How to use it?
- Equation:
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Equation 1-7(4+2x)=-9-4x
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Equation 10x+9=7x
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Equation (x+2)^2+(x-3)^2=2x^2
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Equation 6(3x+1)-3x=11x
- Express {x} in terms of y where:
- -5*x+5*y=-9
- -2*x-1*y=-8
- 1*x-4*y=1
- 4*x+15*y=19
- Integral of d{x}:
- 11x
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Identical expressions
- six (3x+ one)-3x=11x
- 6(3x plus 1) minus 3x equally 11x
- six (3x plus one) minus 3x equally 11x
- 63x+1-3x=11x
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Similar expressions
- 6*3x+1-3x=11x
- 6(3x+1)+3x=11x
- 6(3x-1)-3x=11x
- 6*(3*x+1)-3*x-11*x=0
- 6*(3*x+1)-3x=11*x
6(3x+1)-3x=11x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$15 x = 11 x - 6$$
Move the summands with the unknown x
from the right part to the left part:
$$4 x = -6$$
Divide both parts of the equation by 4
We get the answer: x = -3/2
6*(3*x+1)-3*x = 11*x
Expand brackets in the left part
6*3*x+6*1-3*x = 11*x
Looking for similar summands in the left part:
6 + 15*x = 11*x
Move free summands (without x)
from left part to right part, we given:
$$15 x = 11 x - 6$$
Move the summands with the unknown x
from the right part to the left part:
$$4 x = -6$$
Divide both parts of the equation by 4
x = -6 / (4)
We get the answer: x = -3/2
Sum and product of roots
[src]
sum
-3/2
$$- \frac{3}{2}$$
=
-3/2
$$- \frac{3}{2}$$
product
-3/2
$$- \frac{3}{2}$$
=
-3/2
$$- \frac{3}{2}$$
-3/2
The graph