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6(2x+0.5)=8x-(3x+4) equation

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Numerical solution:

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The solution

You have entered [src]
6*(2*x + 1/2) = 8*x + -3*x - 4
$$6 \left(2 x + \frac{1}{2}\right) = 8 x + \left(- 3 x - 4\right)$$
Detail solution
Given the linear equation:
6*(2*x+(1/2)) = 8*x-(3*x+4)

Expand brackets in the left part
6*2*x+6*1/2) = 8*x-(3*x+4)

Expand brackets in the right part
6*2*x+6*1/2) = 8*x-3*x-4

Looking for similar summands in the right part:
3 + 12*x = -4 + 5*x

Move free summands (without x)
from left part to right part, we given:
$$12 x = 5 x - 7$$
Move the summands with the unknown x
from the right part to the left part:
$$7 x = -7$$
Divide both parts of the equation by 7
x = -7 / (7)

We get the answer: x = -1
The graph
Rapid solution [src]
x1 = -1
$$x_{1} = -1$$
x1 = -1
Sum and product of roots [src]
sum
-1
$$-1$$
=
-1
$$-1$$
product
-1
$$-1$$
=
-1
$$-1$$
-1
Numerical answer [src]
x1 = -1.0
x1 = -1.0