Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation sin(x)+cos(x)=-1
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Equation x^2-3*x+3=0
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Equation √(x^2-1)^3=2*x
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Equation 1/(x-3)^2-8/(x-3)+15=0
- Express {x} in terms of y where:
- -11*x+10*y=-9
- -9*x-4*y=-20
- -6*x-12*y=9
- 6*x-2*y=-10
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Identical expressions
- six (2x+ zero . five)=8x-(3x+ four)
- 6(2x plus 0.5) equally 8x minus (3x plus 4)
- six (2x plus zero . five) equally 8x minus (3x plus four)
- 62x+0.5=8x-3x+4
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Similar expressions
- 6(2x+0.5)=8x+(3x+4)
- 6(2x+0.5)=8x-(3x-4)
- 6(2x-0.5)=8x-(3x+4)
6(2x+0.5)=8x-(3x+4) equation
The teacher will be very surprised to see your correct solution 😉
The solution
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6*(2*x + 1/2) = 8*x + -3*x - 4
$$6 \left(2 x + \frac{1}{2}\right) = 8 x + \left(- 3 x - 4\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$12 x = 5 x - 7$$
Move the summands with the unknown x
from the right part to the left part:
$$7 x = -7$$
Divide both parts of the equation by 7
We get the answer: x = -1
6*(2*x+(1/2)) = 8*x-(3*x+4)
Expand brackets in the left part
6*2*x+6*1/2) = 8*x-(3*x+4)
Expand brackets in the right part
6*2*x+6*1/2) = 8*x-3*x-4
Looking for similar summands in the right part:
3 + 12*x = -4 + 5*x
Move free summands (without x)
from left part to right part, we given:
$$12 x = 5 x - 7$$
Move the summands with the unknown x
from the right part to the left part:
$$7 x = -7$$
Divide both parts of the equation by 7
x = -7 / (7)
We get the answer: x = -1