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(S+3,24)(23s+1) equation

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Numerical solution:

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The solution

You have entered [src]
/    81\               
|s + --|*(23*s + 1) = 0
\    25/               
$$\left(s + \frac{81}{25}\right) \left(23 s + 1\right) = 0$$
Detail solution
Expand the expression in the equation
$$\left(s + \frac{81}{25}\right) \left(23 s + 1\right) = 0$$
We get the quadratic equation
$$23 s^{2} + \frac{1888 s}{25} + \frac{81}{25} = 0$$
This equation is of the form
a*s^2 + b*s + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$s_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$s_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 23$$
$$b = \frac{1888}{25}$$
$$c = \frac{81}{25}$$
, then
D = b^2 - 4 * a * c = 

(1888/25)^2 - 4 * (23) * (81/25) = 3378244/625

Because D > 0, then the equation has two roots.
s1 = (-b + sqrt(D)) / (2*a)

s2 = (-b - sqrt(D)) / (2*a)

or
$$s_{1} = - \frac{1}{23}$$
$$s_{2} = - \frac{81}{25}$$
Rapid solution [src]
     -81 
s1 = ----
      25 
$$s_{1} = - \frac{81}{25}$$
s2 = -1/23
$$s_{2} = - \frac{1}{23}$$
s2 = -1/23
Sum and product of roots [src]
sum
  81       
- -- - 1/23
  25       
$$- \frac{81}{25} - \frac{1}{23}$$
=
-1888 
------
 575  
$$- \frac{1888}{575}$$
product
-81*(-1)
--------
 25*23  
$$- \frac{-81}{575}$$
=
 81
---
575
$$\frac{81}{575}$$
81/575
Numerical answer [src]
s1 = -0.0434782608695652
s2 = -3.24
s2 = -3.24