Mister Exam
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How to use it?
- Equation:
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Equation x+12=5
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Equation 3/(x-5)+8/x=2
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Equation (5x-2)*(-x+3)=0
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Equation 1-x/2=x/3
- Express {x} in terms of y where:
- 18*x+17*y=-14
- 16*x-17*y=-15
- -4*x-4*y=19
- 12*x+1*y=15
- Graphing y =:
- 1-x/2
- x/3
- Limit of the function:
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1-x/2
- Derivative of:
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x/3
- Integral of d{x}:
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x/3
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Identical expressions
- one -x/ two =x/ three
- 1 minus x divide by 2 equally x divide by 3
- one minus x divide by two equally x divide by three
- 1-x divide by 2=x divide by 3
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Similar expressions
- x=(1-x)/2
- cos(x)/3=1
- 1+x/2=x/3
- arcctg((1-x)/2/x)+arccos(2x)=pi/2
- (95-x)/(37,72*log10(90/(x-5)))*sqrt(40/(150-x))=1
- asin(y/2)=-2*sqrt(1-3*x)/3
1-x/2=x/3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$- \frac{x}{2} = \frac{x}{3} - 1$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-5\right) x}{6} = -1$$
Divide both parts of the equation by -5/6
We get the answer: x = 6/5
1-x/2 = x/3
Move free summands (without x)
from left part to right part, we given:
$$- \frac{x}{2} = \frac{x}{3} - 1$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-5\right) x}{6} = -1$$
Divide both parts of the equation by -5/6
x = -1 / (-5/6)
We get the answer: x = 6/5
Sum and product of roots
[src]
sum
6/5
$$\frac{6}{5}$$
=
6/5
$$\frac{6}{5}$$
product
6/5
$$\frac{6}{5}$$
=
6/5
$$\frac{6}{5}$$
6/5
The graph