Mister Exam
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How to use it?
- Equation:
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Equation x^2=-100
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Equation 2x^2-3x+1=0
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Equation 2*x^2-5*x+2=0
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Equation x^3+x^2-9*x-9=0
- Express {x} in terms of y where:
- 4*x-4*y=-19
- 5*x-4*y=14
- -7*x+15*y=7
- -2*x+17*y=-3
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Identical expressions
- one /3x+ twelve =x
- 1 divide by 3x plus 12 equally x
- one divide by 3x plus twelve equally x
- 1 divide by 3x+12=x
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Similar expressions
- 1/3x-12=x
1/3x+12=x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$\frac{x}{3} = x - 12$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-2\right) x}{3} = -12$$
Divide both parts of the equation by -2/3
We get the answer: x = 18
1/3*x+12 = x
Move free summands (without x)
from left part to right part, we given:
$$\frac{x}{3} = x - 12$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-2\right) x}{3} = -12$$
Divide both parts of the equation by -2/3
x = -12 / (-2/3)
We get the answer: x = 18
The graph