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- Equation:
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Equation 9,4x-7,8x+0,52=1
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Equation k^2-6*k+9=0
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Equation sinx+cosx=0
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Equation 17-8y=4y-7
- Express {x} in terms of y where:
- 15*x+15*y=16
- -4*x+18*y=-14
- 8*x+7*y=-13
- -12*x+3*y=-9
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Identical expressions
- nine ,4x- seven ,8x+ zero , fifty-two = one
- 9,4x minus 7,8x plus 0,52 equally 1
- nine ,4x minus seven ,8x plus zero , fifty minus two equally one
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Similar expressions
- 9,4x+7,8x+0,52=1
- 9,4x-7,8x-0,52=1
9,4x-7,8x+0,52=1 equation
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The solution
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[src]
47*x 39*x 13 ---- - ---- + -- = 1 5 5 25
$$- \frac{39 x}{5} + \frac{47 x}{5} + \frac{13}{25} = 1$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$\frac{8 x}{5} = \frac{12}{25}$$
Divide both parts of the equation by 8/5
We get the answer: x = 3/10
(47/5)*x-(39/5)*x+(13/25) = 1
Expand brackets in the left part
47/5x-39/5x+13/25 = 1
Looking for similar summands in the left part:
13/25 + 8*x/5 = 1
Move free summands (without x)
from left part to right part, we given:
$$\frac{8 x}{5} = \frac{12}{25}$$
Divide both parts of the equation by 8/5
x = 12/25 / (8/5)
We get the answer: x = 3/10
Sum and product of roots
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sum
3/10
$$\left(\frac{3}{10}\right)$$
=
3/10
$$\frac{3}{10}$$
product
3/10
$$\left(\frac{3}{10}\right)$$
=
3/10
$$\frac{3}{10}$$
The graph