Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation (x+3)(x+1)(x-7)=(x+3)(x+1)(x-8)
- Equation (|14-2x|)=3-5x
- Equation (15*x-28)/2=76
-
Equation 4(x-1)(x-7)=3x^2-16x
- Express {x} in terms of y where:
- 8*x-7*y=-13
- 9*x+18*y=6
- 15*x-15*y=16
- (x^2+y^2-1)^3+x^2*y^3=0
- Derivative of:
-
3-5x
- Graphing y =:
- 3-5x
-
Identical expressions
- (| fourteen -2x|)= three -5x
- ( module of 14 minus 2x|) equally 3 minus 5x
- ( module of fourteen minus 2x|) equally three minus 5x
- |14-2x|=3-5x
-
Similar expressions
- (|14-2x|)=3+5x
- f*x=(3*x^4-4*x^3-5*x+12)/x
- (|14+2x|)=3-5x
- 10x-9=6(7x+3)-5x
(|14-2x|)=3-5x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$2 x - 14 \geq 0$$
or
$$7 \leq x \wedge x < \infty$$
we get the equation
$$5 x + \left(2 x - 14\right) - 3 = 0$$
after simplifying we get
$$7 x - 17 = 0$$
the solution in this interval:
$$x_{1} = \frac{17}{7}$$
but x1 not in the inequality interval
2.
$$2 x - 14 < 0$$
or
$$-\infty < x \wedge x < 7$$
we get the equation
$$5 x + \left(14 - 2 x\right) - 3 = 0$$
after simplifying we get
$$3 x + 11 = 0$$
the solution in this interval:
$$x_{2} = - \frac{11}{3}$$
The final answer:
$$x_{1} = - \frac{11}{3}$$
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$2 x - 14 \geq 0$$
or
$$7 \leq x \wedge x < \infty$$
we get the equation
$$5 x + \left(2 x - 14\right) - 3 = 0$$
after simplifying we get
$$7 x - 17 = 0$$
the solution in this interval:
$$x_{1} = \frac{17}{7}$$
but x1 not in the inequality interval
2.
$$2 x - 14 < 0$$
or
$$-\infty < x \wedge x < 7$$
we get the equation
$$5 x + \left(14 - 2 x\right) - 3 = 0$$
after simplifying we get
$$3 x + 11 = 0$$
the solution in this interval:
$$x_{2} = - \frac{11}{3}$$
The final answer:
$$x_{1} = - \frac{11}{3}$$
Sum and product of roots
[src]
sum
-11/3
$$- \frac{11}{3}$$
=
-11/3
$$- \frac{11}{3}$$
product
-11/3
$$- \frac{11}{3}$$
=
-11/3
$$- \frac{11}{3}$$
-11/3