Mister Exam
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How to use it?
- Equation:
-
Equation 25x^3-10x^2+x=0
- Equation |6b-9|=-20
- Equation x1+x2+x3+x4+x5+x6+x7+x8=0
- Equation sin(6πsinx)+√3cos(6πsinx)=2
- Express {x} in terms of y where:
- (x^2+y^2-1)^3+x^2*y^3=0
- -1*x-19*y=-10
- 5*x+5*y=20
- 4*x-16*y=6
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Identical expressions
- |6b- nine |=- twenty
- module of 6b minus 9| equally minus 20
- module of 6b minus nine | equally minus twenty
-
Similar expressions
- |6b-9|=+20
- |6b+9|=-20
|6b-9|=-20 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$6 b - 9 \geq 0$$
or
$$\frac{3}{2} \leq b \wedge b < \infty$$
we get the equation
$$\left(6 b - 9\right) + 20 = 0$$
after simplifying we get
$$6 b + 11 = 0$$
the solution in this interval:
$$b_{1} = - \frac{11}{6}$$
but b1 not in the inequality interval
2.
$$6 b - 9 < 0$$
or
$$-\infty < b \wedge b < \frac{3}{2}$$
we get the equation
$$\left(9 - 6 b\right) + 20 = 0$$
after simplifying we get
$$29 - 6 b = 0$$
the solution in this interval:
$$b_{2} = \frac{29}{6}$$
but b2 not in the inequality interval
The final answer:
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$6 b - 9 \geq 0$$
or
$$\frac{3}{2} \leq b \wedge b < \infty$$
we get the equation
$$\left(6 b - 9\right) + 20 = 0$$
after simplifying we get
$$6 b + 11 = 0$$
the solution in this interval:
$$b_{1} = - \frac{11}{6}$$
but b1 not in the inequality interval
2.
$$6 b - 9 < 0$$
or
$$-\infty < b \wedge b < \frac{3}{2}$$
we get the equation
$$\left(9 - 6 b\right) + 20 = 0$$
after simplifying we get
$$29 - 6 b = 0$$
the solution in this interval:
$$b_{2} = \frac{29}{6}$$
but b2 not in the inequality interval
The final answer: