Mister Exam
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How to use it?
- Equation:
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Equation x^2-x-7=0
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Equation 141*10^(-6)*x*3*sqrt(2)=sqrt((1-19881*10^(-12)*x^2)^2+9)
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Equation e^x=4
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Equation x^3=x^2-7x+7
- Express {x} in terms of y where:
- -6*x-13*y=17
- -7*x+5*y=1
- -6*x-19*y=7
- -19*x-4*y=-19
- Derivative of:
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5x
- Integral of d{x}:
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5x
- Graphing y =:
- 5x
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Identical expressions
- -9x- fifty-six =5x
- minus 9x minus 56 equally 5x
- minus 9x minus fifty minus six equally 5x
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Similar expressions
- 9x-56=5x
- 5^x=3
- 8x−5(x+1)=−2x.
- 6*x^2-5*x+1=0
- 4*(x-3)-16=5*(x-5)
- -9x+56=5x
-9x-56=5x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$- 9 x = 5 x + 56$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-14\right) x = 56$$
Divide both parts of the equation by -14
We get the answer: x = -4
-9*x-56 = 5*x
Move free summands (without x)
from left part to right part, we given:
$$- 9 x = 5 x + 56$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-14\right) x = 56$$
Divide both parts of the equation by -14
x = 56 / (-14)
We get the answer: x = -4
The graph