Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation cos(x)=-3
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Equation x²-6x+5=0
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Equation (5+7*a)*15=-30
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Equation 3+11y=203+y
- Express {x} in terms of y where:
- 20*x-19*y=-17
- -14*x-12*y=-9
- -3*x-7*y=-17
- -18*x-12*y=-9
- Sum of series:
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16
- Derivative of:
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16
- Integral of d{x}:
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16
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Identical expressions
- -5x-11y= sixteen
- minus 5x minus 11y equally 16
- minus 5x minus 11y equally sixteen
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Similar expressions
- 5x-11y=16
- -5x+11y=16
-5x-11y=16 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 5 x = 11 y + 16$$
Divide both parts of the equation by -5
We get the answer: x = -16/5 - 11*y/5
-5*x-11*y = 16
Looking for similar summands in the left part:
-11*y - 5*x = 16
Move the summands with the other variables
from left part to right part, we given:
$$- 5 x = 11 y + 16$$
Divide both parts of the equation by -5
x = 16 + 11*y / (-5)
We get the answer: x = -16/5 - 11*y/5
The graph
Rapid solution
[src]
16 11*re(y) 11*I*im(y)
x1 = - -- - -------- - ----------
5 5 5
$$x_{1} = - \frac{11 \operatorname{re}{\left(y\right)}}{5} - \frac{11 i \operatorname{im}{\left(y\right)}}{5} - \frac{16}{5}$$
x1 = -11*re(y)/5 - 11*i*im(y)/5 - 16/5
Sum and product of roots
[src]
sum
16 11*re(y) 11*I*im(y) - -- - -------- - ---------- 5 5 5
$$- \frac{11 \operatorname{re}{\left(y\right)}}{5} - \frac{11 i \operatorname{im}{\left(y\right)}}{5} - \frac{16}{5}$$
=
16 11*re(y) 11*I*im(y) - -- - -------- - ---------- 5 5 5
$$- \frac{11 \operatorname{re}{\left(y\right)}}{5} - \frac{11 i \operatorname{im}{\left(y\right)}}{5} - \frac{16}{5}$$
product
16 11*re(y) 11*I*im(y) - -- - -------- - ---------- 5 5 5
$$- \frac{11 \operatorname{re}{\left(y\right)}}{5} - \frac{11 i \operatorname{im}{\left(y\right)}}{5} - \frac{16}{5}$$
=
16 11*re(y) 11*I*im(y) - -- - -------- - ---------- 5 5 5
$$- \frac{11 \operatorname{re}{\left(y\right)}}{5} - \frac{11 i \operatorname{im}{\left(y\right)}}{5} - \frac{16}{5}$$
-16/5 - 11*re(y)/5 - 11*i*im(y)/5