3+11y=203+y equation
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The solution
Detail solution
Given the linear equation:
3+11*y = 203+y
Move free summands (without y)
from left part to right part, we given:
$$11 y = y + 200$$
Move the summands with the unknown y
from the right part to the left part:
$$10 y = 200$$
Divide both parts of the equation by 10
y = 200 / (10)
We get the answer: y = 20
Sum and product of roots
[src]
$$20$$
$$20$$
$$20$$
$$20$$