Mister Exam
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How to use it?
- Equation:
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Equation 12-(4-x)^2=x(3-x)
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Equation 3^x=-3
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Equation x^2-7*x+5=0
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Equation (x+1)^2=0
- Express {x} in terms of y where:
- -11*x-14*y=6
- -17*x+9*y=-18
- 15*x+6*y=16
- 16*x-1*y=17
- Graphing y =:
- -3x+9
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Identical expressions
- -3x+ nine = zero
- minus 3x plus 9 equally 0
- minus 3x plus nine equally zero
- -3x+9=O
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Similar expressions
- 12+4(x-3)-2=(5-3x)+9
- -9-2*(5-x)=-3*x+9
- -3x-9=0
- 3x+9=0
- x^2+2(a-3)x+9-2a=0
- x^2-3*x+9=0
-3x+9=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$- 3 x = -9$$
Divide both parts of the equation by -3
We get the answer: x = 3
-3*x+9 = 0
Move free summands (without x)
from left part to right part, we given:
$$- 3 x = -9$$
Divide both parts of the equation by -3
x = -9 / (-3)
We get the answer: x = 3
The graph