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(m+8)*(m-7)=0 equation

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Numerical solution:

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The solution

You have entered [src]
(m + 8)*(m - 7) = 0
$$\left(m - 7\right) \left(m + 8\right) = 0$$
Detail solution
Expand the expression in the equation
$$\left(m - 7\right) \left(m + 8\right) = 0$$
We get the quadratic equation
$$m^{2} + m - 56 = 0$$
This equation is of the form
a*m^2 + b*m + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$m_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$m_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 1$$
$$c = -56$$
, then
D = b^2 - 4 * a * c = 

(1)^2 - 4 * (1) * (-56) = 225

Because D > 0, then the equation has two roots.
m1 = (-b + sqrt(D)) / (2*a)

m2 = (-b - sqrt(D)) / (2*a)

or
$$m_{1} = 7$$
$$m_{2} = -8$$
Rapid solution [src]
m1 = -8
$$m_{1} = -8$$
m2 = 7
$$m_{2} = 7$$
m2 = 7
Sum and product of roots [src]
sum
-8 + 7
$$-8 + 7$$
=
-1
$$-1$$
product
-8*7
$$- 56$$
=
-56
$$-56$$
-56
Numerical answer [src]
m1 = 7.0
m2 = -8.0
m2 = -8.0