Expand the expression in the equation
$$\left(m - 7\right) \left(m + 8\right) = 0$$
We get the quadratic equation
$$m^{2} + m - 56 = 0$$
This equation is of the form
a*m^2 + b*m + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$m_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$m_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 1$$
$$c = -56$$
, then
D = b^2 - 4 * a * c =
(1)^2 - 4 * (1) * (-56) = 225
Because D > 0, then the equation has two roots.
m1 = (-b + sqrt(D)) / (2*a)
m2 = (-b - sqrt(D)) / (2*a)
or
$$m_{1} = 7$$
$$m_{2} = -8$$