Mister Exam
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How to use it?
- Equation:
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Equation 14x-25=20x+9
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Equation (x-5)^2=(x+15)^2
- Equation log(x-7)25=2
- Equation ((8z-1)/5)-((3z+3)/4)=((50-2z)/9)+1
- Express {x} in terms of y where:
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Identical expressions
- log(x- seven) twenty-five = two
- logarithm of (x minus 7)25 equally 2
- logarithm of (x minus seven) twenty minus five equally two
- logx-725=2
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Similar expressions
- log(x+7)25=2
log(x-7)25=2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$25 \log{\left(x - 7 \right)} = 2$$
$$25 \log{\left(x - 7 \right)} = 2$$
Let's divide both parts of the equation by the multiplier of log =25
$$\log{\left(x - 7 \right)} = \frac{2}{25}$$
This equation is of the form:
By definition log
then
$$x - 7 = e^{\frac{2}{25}}$$
simplify
$$x - 7 = e^{\frac{2}{25}}$$
$$x = e^{\frac{2}{25}} + 7$$
$$25 \log{\left(x - 7 \right)} = 2$$
$$25 \log{\left(x - 7 \right)} = 2$$
Let's divide both parts of the equation by the multiplier of log =25
$$\log{\left(x - 7 \right)} = \frac{2}{25}$$
This equation is of the form:
log(v)=p
By definition log
v=e^p
then
$$x - 7 = e^{\frac{2}{25}}$$
simplify
$$x - 7 = e^{\frac{2}{25}}$$
$$x = e^{\frac{2}{25}} + 7$$
Sum and product of roots
[src]
sum
2/25 7 + e
$$e^{\frac{2}{25}} + 7$$
=
2/25 7 + e
$$e^{\frac{2}{25}} + 7$$
product
2/25 7 + e
$$e^{\frac{2}{25}} + 7$$
=
2/25 7 + e
$$e^{\frac{2}{25}} + 7$$
7 + exp(2/25)