4*x2+7=7+24*x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
4*x2+7 = 7+24*x
Move free summands (without x)
from left part to right part, we given:
$$4 x_{2} = 24 x$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-24\right) x + 4 x_{2} = 0$$
Divide both parts of the equation by (-24*x + 4*x2)/x
x = 0 / ((-24*x + 4*x2)/x)
We get the answer: x = x2/6
re(x2) I*im(x2)
x1 = ------ + --------
6 6
$$x_{1} = \frac{\operatorname{re}{\left(x_{2}\right)}}{6} + \frac{i \operatorname{im}{\left(x_{2}\right)}}{6}$$
x1 = re(x2)/6 + i*im(x2)/6
Sum and product of roots
[src]
re(x2) I*im(x2)
------ + --------
6 6
$$\frac{\operatorname{re}{\left(x_{2}\right)}}{6} + \frac{i \operatorname{im}{\left(x_{2}\right)}}{6}$$
re(x2) I*im(x2)
------ + --------
6 6
$$\frac{\operatorname{re}{\left(x_{2}\right)}}{6} + \frac{i \operatorname{im}{\left(x_{2}\right)}}{6}$$
re(x2) I*im(x2)
------ + --------
6 6
$$\frac{\operatorname{re}{\left(x_{2}\right)}}{6} + \frac{i \operatorname{im}{\left(x_{2}\right)}}{6}$$
re(x2) I*im(x2)
------ + --------
6 6
$$\frac{\operatorname{re}{\left(x_{2}\right)}}{6} + \frac{i \operatorname{im}{\left(x_{2}\right)}}{6}$$