Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 2x-3(x+3)=-5
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Equation x/4+x=4
-
Equation tan(x)=-1/2
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Equation 4/(x-4)=-5
- Express {x} in terms of y where:
- 18*x+12*y=18
- -17*x+2*y=9
- 14*x-16*y=19
- 18*x+1*y=-11
- Graphing y =:
- 4/(x-4)
- Derivative of:
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-5
- -5
- Integral of d{x}:
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-5
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Identical expressions
- four /(x- four)=- five
- 4 divide by (x minus 4) equally minus 5
- four divide by (x minus four) equally minus five
- 4/x-4=-5
- 4 divide by (x-4)=-5
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Similar expressions
- 4/(x+4)=-5
- (x^2-3*x-4)/(x-4)=0
- 4^(x-4)/(x-4)=-5
- 4/(x-4)=+5
- (2*x-4)/(x-4)-(x^2-4*x+1)/(x-4)^2=0
4/(x-4)=-5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{4}{x - 4} = -5$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
so we get the equation
$$\frac{\left(-1\right) 4}{5} = x - 4$$
$$- \frac{4}{5} = x - 4$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x - \frac{16}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = - \frac{16}{5}$$
Divide both parts of the equation by -1
We get the answer: x = 16/5
$$\frac{4}{x - 4} = -5$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
a1 = 4
b1 = -4 + x
a2 = 1
b2 = -1/5
so we get the equation
$$\frac{\left(-1\right) 4}{5} = x - 4$$
$$- \frac{4}{5} = x - 4$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x - \frac{16}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = - \frac{16}{5}$$
Divide both parts of the equation by -1
x = -16/5 / (-1)
We get the answer: x = 16/5
Sum and product of roots
[src]
sum
16/5
$$\frac{16}{5}$$
=
16/5
$$\frac{16}{5}$$
product
16/5
$$\frac{16}{5}$$
=
16/5
$$\frac{16}{5}$$
16/5
The graph