Mister Exam
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How to use it?
- Equation:
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Equation -24-y=-16
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Equation 4(x-6)=x-9
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Equation x*(x^2+8*x+16)=5*(x+4)
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Equation -x^2+4x+3=x^2-x-(1+2x^2)
- Express {x} in terms of y where:
- 10*x-15*y=16
- -18*x-6*y=-1
- -6*x-10*y=19
- -1*x-17*y=-12
- Derivative of:
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-5
- -5
- Integral of d{x}:
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-5
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Identical expressions
- 2x- three (x+ three)=- five
- 2x minus 3(x plus 3) equally minus 5
- 2x minus three (x plus three) equally minus five
- 2x-3x+3=-5
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Similar expressions
- (-3x-4)/(2(x-3)(x+3))=1
- (-5^2)*x-3*x+36=0
- 2x-3(x+3)=+5
- 2x-3(x-3)=-5
- 2x+3(x+3)=-5
2x-3(x+3)=-5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- x = 4$$
Divide both parts of the equation by -1
We get the answer: x = -4
2*x-3*(x+3) = -5
Expand brackets in the left part
2*x-3*x-3*3 = -5
Looking for similar summands in the left part:
-9 - x = -5
Move free summands (without x)
from left part to right part, we given:
$$- x = 4$$
Divide both parts of the equation by -1
x = 4 / (-1)
We get the answer: x = -4
The graph