Mister Exam
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How to use it?
- Equation:
- Equation x^3+11x^2-9x-99=0
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Equation 43+x=500÷10
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Equation 1/x^2+4/x-12=0
- Equation (x^2+20)/(x^2-4)=(x-3)/(x+2)+(6)/(x-2)
- Express {x} in terms of y where:
- -1*x-19*y=-10
- (x^2+y^2-1)^3+x^2*y^3=0
- 4*x-16*y=6
- -14*x-1*y=3
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Identical expressions
- forty-three +x= five hundred ÷ ten
- 43 plus x equally 500÷10
- forty minus three plus x equally five hundred ÷ ten
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Similar expressions
- 43-x=500÷10
- 43+(x-46*25):75=193
- 4^(3+x)=16
- 543+(x*2)+x=1240,8
43+x=500÷10 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$x = 7$$
We get the answer: x = 7
43+x = 500/10
Move free summands (without x)
from left part to right part, we given:
$$x = 7$$
We get the answer: x = 7
Sum and product of roots
[src]
sum
7
$$\left(7\right)$$
=
7
$$7$$
product
7
$$\left(7\right)$$
=
7
$$7$$
The graph