Mister Exam
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How to use it?
- Equation:
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Equation x^3=3
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Equation 5-x^2=0
- Equation (-5*x+3)*(-x+8)=0
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Equation x^2+6=5x
- Express {x} in terms of y where:
- -6*x+11*y=-5
- -3*x-19*y=-9
- -19*x-15*y=15
- 13*x-11*y=16
- Derivative of:
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13x
- Integral of d{x}:
- 13x
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Identical expressions
- five (x- two , four)=13x
- 5(x minus 2,4) equally 13x
- five (x minus two , four) equally 13x
- 5x-2,4=13x
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Similar expressions
- 0,5x-2,4=31,8
- 12^x+5^x=13^x
- -7,2(x-13)(x+2,9)=0
- 5(x+2,4)=13x
5(x-2,4)=13x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Move free summands (without x)
from left part to right part, we given:
$$5 x = 13 x + 12$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-8\right) x = 12$$
Divide both parts of the equation by -8
We get the answer: x = -3/2
5*(x-(12/5)) = 13*x
Expand brackets in the left part
5*x+5*12/5) = 13*x
Move free summands (without x)
from left part to right part, we given:
$$5 x = 13 x + 12$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-8\right) x = 12$$
Divide both parts of the equation by -8
x = 12 / (-8)
We get the answer: x = -3/2
Sum and product of roots
[src]
sum
-3/2
$$- \frac{3}{2}$$
=
-3/2
$$- \frac{3}{2}$$
product
-3/2
$$- \frac{3}{2}$$
=
-3/2
$$- \frac{3}{2}$$
-3/2
The graph