Mister Exam
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How to use it?
- Equation:
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Equation sqrt(x^2-x-1)-sqrt(x)=1
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Equation sin(x)=2/3
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Equation 5+2x=3(2x-5)-8
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Equation log(x)
- Express {x} in terms of y where:
- 10*x-19*y=3
- 17*x-20*y=6
- -2*x-1*y=-8
- -4*x+20*y=10
- Derivative of:
- 5+2x
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Identical expressions
- five +2x= three (2x- five)- eight
- 5 plus 2x equally 3(2x minus 5) minus 8
- five plus 2x equally three (2x minus five) minus eight
- 5+2x=32x-5-8
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Similar expressions
- 5+2x=3(2x+5)-8
- 5+2x=3(2x-5)+8
- (sqrt(5)-2)^x+(sqrt(5)+2)^x=18
- (sqrt(5)+2)^x-1=(sqrt(5)-2)^x-1/x+1
- 5-2x=3(2x-5)-8
5+2x=3(2x-5)-8 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$2 x = 6 x - 28$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-4\right) x = -28$$
Divide both parts of the equation by -4
We get the answer: x = 7
5+2*x = 3*(2*x-5)-8
Expand brackets in the right part
5+2*x = 3*2*x-3*5-8
Looking for similar summands in the right part:
5 + 2*x = -23 + 6*x
Move free summands (without x)
from left part to right part, we given:
$$2 x = 6 x - 28$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-4\right) x = -28$$
Divide both parts of the equation by -4
x = -28 / (-4)
We get the answer: x = 7
The graph