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(x^2-7*x-11)-(5*x^2-13*x-18)=16-4*x^2 equation

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Numerical solution:

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The solution

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 2                   2                       2
x  - 7*x - 11 + - 5*x  + 13*x + 18 = 16 - 4*x 
$$\left(\left(- 5 x^{2} + 13 x\right) + 18\right) + \left(\left(x^{2} - 7 x\right) - 11\right) = 16 - 4 x^{2}$$
Detail solution
Given the linear equation:
(x^2-7*x-11)-(5*x^2-13*x-18) = 16-4*x^2

Expand brackets in the left part
x+2-7*x-11-5*x-2+13*x+18 = 16-4*x^2

Looking for similar summands in the left part:
7 - 4*x^2 + 6*x = 16-4*x^2

Move free summands (without x)
from left part to right part, we given:
$$- 4 x^{2} + 6 x = 9 - 4 x^{2}$$
Divide both parts of the equation by (-4*x^2 + 6*x)/x
x = 9 - 4*x^2 / ((-4*x^2 + 6*x)/x)

We get the answer: x = 3/2
The graph
Sum and product of roots [src]
sum
3/2
$$\frac{3}{2}$$
=
3/2
$$\frac{3}{2}$$
product
3/2
$$\frac{3}{2}$$
=
3/2
$$\frac{3}{2}$$
3/2
Rapid solution [src]
x1 = 3/2
$$x_{1} = \frac{3}{2}$$
x1 = 3/2
Numerical answer [src]
x1 = 1.5
x1 = 1.5