3*x^2-18=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 3$$
$$b = 0$$
$$c = -18$$
, then
D = b^2 - 4 * a * c =
(0)^2 - 4 * (3) * (-18) = 216
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = \sqrt{6}$$
Simplify$$x_{2} = - \sqrt{6}$$
Simplify
Vieta's Theorem
rewrite the equation
$$3 x^{2} - 18 = 0$$
of
$$a x^{2} + b x + c = 0$$
as reduced quadratic equation
$$x^{2} + \frac{b x}{a} + \frac{c}{a} = 0$$
$$x^{2} - 6 = 0$$
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = -6$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = 0$$
$$x_{1} x_{2} = -6$$
$$x_{1} = - \sqrt{6}$$
$$x_{2} = \sqrt{6}$$
Sum and product of roots
[src]
$$\left(- \sqrt{6} + 0\right) + \sqrt{6}$$
$$0$$
$$\sqrt{6} \cdot 1 \left(- \sqrt{6}\right)$$
$$-6$$