cos(x)/5=-1 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
5cos(x)=−1- this is the simplest trigonometric equation
Divide both parts of the equation by 1/5
The equation is transformed to
cos(x)=−5As right part of the equation
modulo =
True
but cos
can no be more than 1 or less than -1
so the solution of the equation d'not exist.
The graph
x1 = -re(acos(-5)) + 2*pi - I*im(acos(-5))
x1=−re(acos(−5))+2π−iim(acos(−5))
x2 = I*im(acos(-5)) + re(acos(-5))
x2=re(acos(−5))+iim(acos(−5))
Sum and product of roots
[src]
0 + -re(acos(-5)) + 2*pi - I*im(acos(-5)) + I*im(acos(-5)) + re(acos(-5))
(re(acos(−5))+iim(acos(−5)))−(−2π+re(acos(−5))+iim(acos(−5)))
1*(-re(acos(-5)) + 2*pi - I*im(acos(-5)))*(I*im(acos(-5)) + re(acos(-5)))
(re(acos(−5))+iim(acos(−5)))1(−re(acos(−5))+2π−iim(acos(−5)))
-(I*im(acos(-5)) + re(acos(-5)))*(-2*pi + I*im(acos(-5)) + re(acos(-5)))
−(re(acos(−5))+iim(acos(−5)))(−2π+re(acos(−5))+iim(acos(−5)))
-(i*im(acos(-5)) + re(acos(-5)))*(-2*pi + i*im(acos(-5)) + re(acos(-5)))
x1 = 3.14159265358979 + 2.29243166956118*i
x2 = 3.14159265358979 - 2.29243166956118*i
x2 = 3.14159265358979 - 2.29243166956118*i