Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 0,8(x-2)+2,6=0,5(7+x)
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Equation x^2+1=(x+1)^2
- Equation log7(3-x)=2log7(4)
- Equation (c-4)(c+4)
- Express {x} in terms of y where:
- 9*x+18*y=6
- 15*x-15*y=16
- sqrt(x^2+y^2+4x-6y-12)+(x^2+10x-27)=8-|y-9|+|y-3|
- (x^2+y^2-1)^3+x^2*y^3=0
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Identical expressions
- (c- four)(c+ four)
- (c minus 4)(c plus 4)
- (c minus four)(c plus four)
- c-4c+4
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Similar expressions
- (c+4)(c+4)
- (c-4)(c-4)
(c-4)(c+4) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Expand the expression in the equation
We get the quadratic equation
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
where D = b^2 - 4*a*c - it is the discriminant.
Because
, then
Because D > 0, then the equation has two roots.
or
We get the quadratic equation
This equation is of the form
a*c^2 + b*c + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
where D = b^2 - 4*a*c - it is the discriminant.
Because
, then
D = b^2 - 4 * a * c =
(0)^2 - 4 * (1) * (-16) = 64
Because D > 0, then the equation has two roots.
c1 = (-b + sqrt(D)) / (2*a)
c2 = (-b - sqrt(D)) / (2*a)
or