Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation x^3=3
-
Equation 5-x^2=0
- Equation (-5*x+3)*(-x+8)=0
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Equation 5x^2+9x+4=0
- Express {x} in terms of y where:
- -6*x+11*y=-5
- -3*x-19*y=-9
- 16*x+14*y=-14
- 3*x-14*y=-2
-
Identical expressions
- 9x-5x- three +2x+ one = four x+ seven -3x+4
- 9x minus 5x minus 3 plus 2x plus 1 equally 4x plus 7 minus 3x plus 4
- 9x minus 5x minus three plus 2x plus one equally four x plus seven minus 3x plus 4
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Similar expressions
- 9x-5x-3-2x+1=4x+7-3x+4
- 9x-5x-3+2x-1=4x+7-3x+4
- 9x-5x-3+2x+1=4x+7-3x-4
- 9x-5x-3+2x+1=4x+7+3x+4
- 9x-5x-3+2x+1=4x-7-3x+4
- 9x-5x+3+2x+1=4x+7-3x+4
- 9x+5x-3+2x+1=4x+7-3x+4
9x-5x-3+2x+1=4x+7-3x+4 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
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9*x - 5*x - 3 + 2*x + 1 = 4*x + 7 - 3*x + 4
$$\left(2 x + \left(\left(- 5 x + 9 x\right) - 3\right)\right) + 1 = \left(- 3 x + \left(4 x + 7\right)\right) + 4$$
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$6 x = x + 13$$
Move the summands with the unknown x
from the right part to the left part:
$$5 x = 13$$
Divide both parts of the equation by 5
We get the answer: x = 13/5
9*x-5*x-3+2*x+1 = 4*x+7-3*x+4
Looking for similar summands in the left part:
-2 + 6*x = 4*x+7-3*x+4
Looking for similar summands in the right part:
-2 + 6*x = 11 + x
Move free summands (without x)
from left part to right part, we given:
$$6 x = x + 13$$
Move the summands with the unknown x
from the right part to the left part:
$$5 x = 13$$
Divide both parts of the equation by 5
x = 13 / (5)
We get the answer: x = 13/5
Sum and product of roots
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sum
13/5
$$\frac{13}{5}$$
=
13/5
$$\frac{13}{5}$$
product
13/5
$$\frac{13}{5}$$
=
13/5
$$\frac{13}{5}$$
13/5