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7x^2+8-13x=8x-6

7x^2+8-13x=8x-6 equation

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Numerical solution:

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The solution

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   2                     
7*x  + 8 - 13*x = 8*x - 6
$$- 13 x + \left(7 x^{2} + 8\right) = 8 x - 6$$
Detail solution
Move right part of the equation to
left part with negative sign.

The equation is transformed from
$$- 13 x + \left(7 x^{2} + 8\right) = 8 x - 6$$
to
$$\left(6 - 8 x\right) + \left(- 13 x + \left(7 x^{2} + 8\right)\right) = 0$$
This equation is of the form
a*x^2 + b*x + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 7$$
$$b = -21$$
$$c = 14$$
, then
D = b^2 - 4 * a * c = 

(-21)^2 - 4 * (7) * (14) = 49

Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)

x2 = (-b - sqrt(D)) / (2*a)

or
$$x_{1} = 2$$
$$x_{2} = 1$$
Vieta's Theorem
rewrite the equation
$$- 13 x + \left(7 x^{2} + 8\right) = 8 x - 6$$
of
$$a x^{2} + b x + c = 0$$
as reduced quadratic equation
$$x^{2} + \frac{b x}{a} + \frac{c}{a} = 0$$
$$x^{2} - 3 x + 2 = 0$$
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = -3$$
$$q = \frac{c}{a}$$
$$q = 2$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = 3$$
$$x_{1} x_{2} = 2$$
The graph
Sum and product of roots [src]
sum
1 + 2
$$1 + 2$$
=
3
$$3$$
product
2
$$2$$
=
2
$$2$$
2
Rapid solution [src]
x1 = 1
$$x_{1} = 1$$
x2 = 2
$$x_{2} = 2$$
x2 = 2
Numerical answer [src]
x1 = 1.0
x2 = 2.0
x2 = 2.0
The graph
7x^2+8-13x=8x-6 equation