This equation is of the form a∗x2+b∗x+c=0 A quadratic equation can be solved using the discriminant The roots of the quadratic equation: x1=2aD−b x2=2a−D−b where D=b2−4ac is the discriminant. Because a=7 b=−6 c=5 , then D=b2−4∗a∗c= (−1)7⋅4⋅5+(−6)2=−104 Because D<0, then the equation has no real roots, but complex roots is exists. x1=2a(−b+D) x2=2a(−b−D) or x1=73+726i Simplify x2=73−726i Simplify
Vieta's Theorem
rewrite the equation 7x2−6x+5=0 of ax2+bx+c=0 as reduced quadratic equation x2+abx+ac=0 x2−76x+75=0 px+x2+q=0 where p=ab p=−76 q=ac q=75 Vieta Formulas x1+x2=−p x1x2=q x1+x2=76 x1x2=75