A quadratic equation can be solved using the discriminant. The roots of the quadratic equation: x1=2aD−b x2=2a−D−b where D = b^2 - 4*a*c - it is the discriminant. Because a=5 b=−8 c=3 , then
D = b^2 - 4 * a * c =
(-8)^2 - 4 * (5) * (3) = 4
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or x1=1 x2=53
Vieta's Theorem
rewrite the equation (5x2−8x)+3=0 of ax2+bx+c=0 as reduced quadratic equation x2+abx+ac=0 x2−58x+53=0 px+q+x2=0 where p=ab p=−58 q=ac q=53 Vieta Formulas x1+x2=−p x1x2=q x1+x2=58 x1x2=53