Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- -19*x+10*y=-3
- -4*x-9*y=-2
- 18*x-10*y=-9
- 6*x+16*y=-7
- Equation:
-
Equation 12/x=3
-
Equation 7x-9=40
-
Equation 9*(x-1)=x+15
-
Equation x*x-x+7=0
- Integral of d{x}:
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-3
- Sum of series:
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-3
- Derivative of:
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-3
-
Identical expressions
- - nineteen *x+ ten *y=- three
- minus 19 multiply by x plus 10 multiply by y equally minus 3
- minus nineteen multiply by x plus ten multiply by y equally minus three
- -19x+10y=-3
-
Similar expressions
- -19*x+10*y=+3
- 19*x+10*y=-3
- -19*x-10*y=-3
Express x in terms of y where -19*x+10*y=-3
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 19 x = - 10 y - 3$$
Divide both parts of the equation by -19
We get the answer: x = 3/19 + 10*y/19
-19*x+10*y = -3
Looking for similar summands in the left part:
-19*x + 10*y = -3
Move the summands with the other variables
from left part to right part, we given:
$$- 19 x = - 10 y - 3$$
Divide both parts of the equation by -19
x = -3 - 10*y / (-19)
We get the answer: x = 3/19 + 10*y/19
Rapid solution
[src]
3 10*re(y) 10*I*im(y)
x1 = -- + -------- + ----------
19 19 19
$$x_{1} = \frac{10 \operatorname{re}{\left(y\right)}}{19} + \frac{10 i \operatorname{im}{\left(y\right)}}{19} + \frac{3}{19}$$
x1 = 10*re(y)/19 + 10*i*im(y)/19 + 3/19