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- Equation:
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Equation x^4-7x^2+12=0
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Equation 25^x-6*5^x+5=0
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Equation 5x+4/2+3=9x/4
- Equation sqrt((2-x)/(x-1))-7(sqrt((x-1)/(2-x)))=6
- Express {x} in terms of y where:
- -18*x-1*y=-11
- 17*x-15*y=-17
- 2*x-15*y=-1
- -6*x-17*y=14
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Identical expressions
- 5x+ four / two + three =9x/ four
- 5x plus 4 divide by 2 plus 3 equally 9x divide by 4
- 5x plus four divide by two plus three equally 9x divide by four
- 5x+4 divide by 2+3=9x divide by 4
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Similar expressions
- (5*x+4)/2+3=9*x/4
- 9*x/4=243
- 50-12*x=9*x/4+4
- 5x-4/2+3=9x/4
- 5x+4/2-3=9x/4
- 5*x+4/2+3=9*x/4
5x+4/2+3=9x/4 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$5 x = \frac{9 x}{4} - 5$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{11 x}{4} = -5$$
Divide both parts of the equation by 11/4
We get the answer: x = -20/11
5*x+4/2+3 = 9*x/4
Looking for similar summands in the left part:
5 + 5*x = 9*x/4
Move free summands (without x)
from left part to right part, we given:
$$5 x = \frac{9 x}{4} - 5$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{11 x}{4} = -5$$
Divide both parts of the equation by 11/4
x = -5 / (11/4)
We get the answer: x = -20/11
Sum and product of roots
[src]
sum
20
0 - --
11
$$- \frac{20}{11} + 0$$
=
-20 ---- 11
$$- \frac{20}{11}$$
product
-20 1*---- 11
$$1 \left(- \frac{20}{11}\right)$$
=
-20 ---- 11
$$- \frac{20}{11}$$
-20/11
The graph