Mister Exam
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How to use it?
- Express {x} in terms of y where:
- -18*x-1*y=-11
- 7*x-2*y=20
- -1*x-20*y=-17
- -2*x-14*y=7
- Equation:
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Equation 2x=18-x
-
Equation x^4=(2*x-3)^2
-
Equation 9*x^2=54*x
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Equation cos(x)+sin(x)=0
- Limit of the function:
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-11
- The double integral of:
- -11
- -11
-
Identical expressions
- - eighteen *x- one *y=- eleven
- minus 18 multiply by x minus 1 multiply by y equally minus 11
- minus eighteen multiply by x minus one multiply by y equally minus eleven
- -18x-1y=-11
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Similar expressions
- 18*x-1*y=-11
- -18*x+1*y=-11
- -18*x-1*y=+11
Express x in terms of y where -18*x-1*y=-11
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 18 x = y - 11$$
Divide both parts of the equation by -18
We get the answer: x = 11/18 - y/18
-18*x-1*y = -11
Looking for similar summands in the left part:
-y - 18*x = -11
Move the summands with the other variables
from left part to right part, we given:
$$- 18 x = y - 11$$
Divide both parts of the equation by -18
x = -11 + y / (-18)
We get the answer: x = 11/18 - y/18
Rapid solution
[src]
11 re(y) I*im(y)
x1 = -- - ----- - -------
18 18 18
$$x_{1} = - \frac{\operatorname{re}{\left(y\right)}}{18} - \frac{i \operatorname{im}{\left(y\right)}}{18} + \frac{11}{18}$$
x1 = -re(y)/18 - i*im(y)/18 + 11/18