Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation x^2+4*x+4=0
-
Equation (x^2-4)^2+(x^2-3x-10)^2=0
-
Equation -x/3+x+7=3
-
Equation -20*(x-13)=-220
- Express {x} in terms of y where:
- -14*x+4*y=-16
- -13*x-10*y=5
- 9*x-1*y=17
- -12*x-8*y=13
-
Identical expressions
- 2x*(three +8x)-(4x- three)*(4x+ three)= one ,5x
- 2x multiply by (3 plus 8x) minus (4x minus 3) multiply by (4x plus 3) equally 1,5x
- 2x multiply by (three plus 8x) minus (4x minus three) multiply by (4x plus three) equally one ,5x
- 2x(3+8x)-(4x-3)(4x+3)=1,5x
- 2x3+8x-4x-34x+3=1,5x
-
Similar expressions
- 1,5*x^2-6*x+2=6
- 2x*(3+8x)+(4x-3)*(4x+3)=1,5x
- 2x*(3-8x)-(4x-3)*(4x+3)=1,5x
- 2/3*(1,5*x+0.6)-0.8(5/12*x-0.5)=1
- 2x*(3+8x)-(4x-3)*(4x-3)=1,5x
- 1,5*x^2+20*x+71=0
- 3*x^2+1,5*x-2,5=0
- 2x*(3+8x)-(4x+3)*(4x+3)=1,5x
2x*(3+8x)-(4x-3)*(4x+3)=1,5x equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
3*x
2*x*(3 + 8*x) - (4*x - 3)*(4*x + 3) = ---
2
$$2 x \left(8 x + 3\right) - \left(4 x - 3\right) \left(4 x + 3\right) = \frac{3 x}{2}$$
Detail solution
Given the equation:
Expand expressions:
Reducing, you get:
Move free summands (without x)
from left part to right part, we given:
$$\frac{9 x}{2} = -9$$
Divide both parts of the equation by 9/2
We get the answer: x = -2
2*x*(3+8*x)-(4*x-3)*(4*x+3) = (3/2)*x
Expand expressions:
6*x + 16*x^2 - (4*x - 3)*(4*x + 3) = (3/2)*x
6*x + 16*x^2 + 9 - 16*x^2 = (3/2)*x
2*x*(3+8*x)-(4*x-3)*(4*x+3) = 3*x/2
Reducing, you get:
9 + 9*x/2 = 0
Move free summands (without x)
from left part to right part, we given:
$$\frac{9 x}{2} = -9$$
Divide both parts of the equation by 9/2
x = -9 / (9/2)
We get the answer: x = -2