Mister Exam
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How to use it?
- Equation:
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Equation tg(x)=0
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Equation 12x+5(6-3x)=10-3x
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Equation x^2+x-42=0
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Equation k^2+16=0
- Express {x} in terms of y where:
- 4*x+13*y=13
- 17*x-19*y=1
- -11*x+4*y=-8
- -14*x+1*y=3
- Graphing y =:
- 10-3x
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Identical expressions
- 12x+ five (six -3x)= ten -3x
- 12x plus 5(6 minus 3x) equally 10 minus 3x
- 12x plus five (six minus 3x) equally ten minus 3x
- 12x+56-3x=10-3x
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Similar expressions
- 18x-7x=10-3*(x+4)
- 12x+5(6-3x)=10+3x
- 10-3(x+4)=14-5x
- 12x-5(6-3x)=10-3x
- 10^(-3)*x^2+500*x+50*10^6
- 10-3(x+4)=24-5x
- 12x+5(6+3x)=10-3x
12x+5(6-3x)=10-3x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 3 x = - 3 x - 20$$
Move the summands with the unknown x
from the right part to the left part:
$$0 = -20$$
This equation has no roots
12*x+5*(6-3*x) = 10-3*x
Expand brackets in the left part
12*x+5*6-5*3*x = 10-3*x
Looking for similar summands in the left part:
30 - 3*x = 10-3*x
Move free summands (without x)
from left part to right part, we given:
$$- 3 x = - 3 x - 20$$
Move the summands with the unknown x
from the right part to the left part:
$$0 = -20$$
This equation has no roots
The graph