Mister Exam
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- Equation:
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Equation x=x/2+1
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Equation x^2=6
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Equation (x+10)^2=(x-9)^2
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Equation (7-x)^2=(x+16)^2
- Express {x} in terms of y where:
- -11*x+4*y=-8
- 17*x-11*y=2
- -14*x+1*y=3
- 1*x+19*y=-10
- Integral of d{x}:
- (7-x)^2
- Derivative of:
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(7-x)^2
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Identical expressions
- (seven -x)^ two =(x+ sixteen)^ two
- (7 minus x) squared equally (x plus 16) squared
- (seven minus x) to the power of two equally (x plus sixteen) to the power of two
- (7-x)2=(x+16)2
- 7-x2=x+162
- (7-x)²=(x+16)²
- (7-x) to the power of 2=(x+16) to the power of 2
- 7-x^2=x+16^2
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Similar expressions
- (7-x)^2=(x-16)^2
- (7+x)^2=(x+16)^2
(7-x)^2=(x+16)^2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
Expand expressions:
Reducing, you get:
Move free summands (without x)
from left part to right part, we given:
$$- 46 x = 207$$
Divide both parts of the equation by -46
We get the answer: x = -9/2
(7-x)^2 = (x+16)^2
Expand expressions:
49 + x^2 - 14*x = (x+16)^2
(7-x)^2 = 256 + x^2 + 32*x
Reducing, you get:
-207 - 46*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 46 x = 207$$
Divide both parts of the equation by -46
x = 207 / (-46)
We get the answer: x = -9/2
Sum and product of roots
[src]
sum
-9/2
$$- \frac{9}{2}$$
=
-9/2
$$- \frac{9}{2}$$
product
-9/2
$$- \frac{9}{2}$$
=
-9/2
$$- \frac{9}{2}$$
-9/2
The graph