(10x-6)-(6x-7)=21 equation
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The solution
Detail solution
Given the linear equation:
(10*x-6)-(6*x-7) = 21
Expand brackets in the left part
10*x-6-6*x+7 = 21
Looking for similar summands in the left part:
1 + 4*x = 21
Move free summands (without x)
from left part to right part, we given:
$$4 x = 20$$
Divide both parts of the equation by 4
x = 20 / (4)
We get the answer: x = 5
Sum and product of roots
[src]
$$0 + 5$$
$$5$$
$$1 \cdot 5$$
$$5$$