Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (2-c)+3*(c-3)=-13
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Equation 7(x-1)=3x
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Equation 141*10^(-6)*x*3*sqrt(2)=sqrt((1-19881*10^(-12)*x^2)^2+9)
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Equation -42-x=-23
- Express {x} in terms of y where:
- -20*x+6*y=-12
- -15*x+18*y=0
- 14*x+5*y=11
- -11*x-8*y=-14
- Derivative of:
- 10x-5
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Identical expressions
- 10x- five = six (8x+ three)-5x
- 10x minus 5 equally 6(8x plus 3) minus 5x
- 10x minus five equally six (8x plus three) minus 5x
- 10x-5=68x+3-5x
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Similar expressions
- -x^4+11*x^3-11*x^2-10*x-52=0
- 10x-5=6(8x-3)-5x
- -10*x-5=0
- 10*x-5+6*(8*x+3)-5*x=0
- 10x-5=6(8x+3)+5x
- 10x+5=6(8x+3)-5x
10x-5=6(8x+3)-5x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$10 x = 43 x + 23$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-33\right) x = 23$$
Divide both parts of the equation by -33
We get the answer: x = -23/33
10*x-5 = 6*(8*x+3)-5*x
Expand brackets in the right part
10*x-5 = 6*8*x+6*3-5*x
Looking for similar summands in the right part:
-5 + 10*x = 18 + 43*x
Move free summands (without x)
from left part to right part, we given:
$$10 x = 43 x + 23$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-33\right) x = 23$$
Divide both parts of the equation by -33
x = 23 / (-33)
We get the answer: x = -23/33
Sum and product of roots
[src]
sum
-23 ---- 33
$$- \frac{23}{33}$$
=
-23 ---- 33
$$- \frac{23}{33}$$
product
-23 ---- 33
$$- \frac{23}{33}$$
=
-23 ---- 33
$$- \frac{23}{33}$$
-23/33
The graph