Mister Exam
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How to use it?
- Equation:
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Equation (2-c)+3*(c-3)=-13
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Equation 7(x-1)=3x
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Equation 141*10^(-6)*x*3*sqrt(2)=sqrt((1-19881*10^(-12)*x^2)^2+9)
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Equation -42-x=-23
- Express {x} in terms of y where:
- -20*x+6*y=-12
- -15*x+18*y=0
- 14*x+5*y=11
- -11*x-8*y=-14
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Identical expressions
- - forty-two -x=- twenty-three
- minus 42 minus x equally minus 23
- minus forty minus two minus x equally minus twenty minus three
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Similar expressions
- (X-4)^2-x(x+14)=4
- 4*sin^3x+3*sinx+2*3^1/2-2*3^1/2*cos(2x)=0=0
- 2^x-4*2^(-x)=3
- (9*x-4)*2-(x-14)*2=0
- (3x-2)(3x-1)3x=504
- -42+x=-23
- -42-x=+23
- 42-x=-23
- (2x^2+2x-4)^2-(x^2+x-1)^2=0
- 3sqrt(3/2^(3)-2*3/2+2)=x
-42-x=-23 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$- x = 19$$
Divide both parts of the equation by -1
We get the answer: x = -19
-42-x = -23
Move free summands (without x)
from left part to right part, we given:
$$- x = 19$$
Divide both parts of the equation by -1
x = 19 / (-1)
We get the answer: x = -19
The graph