Mister Exam
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How to use it?
- Equation:
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Equation (2-c)+3*(c-3)=-13
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Equation 7(x-1)=3x
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Equation 141*10^(-6)*x*3*sqrt(2)=sqrt((1-19881*10^(-12)*x^2)^2+9)
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Equation -42-x=-23
- Express {x} in terms of y where:
- -20*x+6*y=-12
- -15*x+18*y=0
- 14*x+5*y=11
- -11*x-8*y=-14
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Identical expressions
- - ten *x- five = zero
- minus 10 multiply by x minus 5 equally 0
- minus ten multiply by x minus five equally zero
- -10x-5=0
- -10*x-5=O
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Similar expressions
- -10*x+5=0
- 10*x-5=0
- 4x^2-10x-5=0
-10*x-5=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$- 10 x = 5$$
Divide both parts of the equation by -10
We get the answer: x = -1/2
-10*x-5 = 0
Move free summands (without x)
from left part to right part, we given:
$$- 10 x = 5$$
Divide both parts of the equation by -10
x = 5 / (-10)
We get the answer: x = -1/2
Sum and product of roots
[src]
sum
-1/2
$$- \frac{1}{2}$$
=
-1/2
$$- \frac{1}{2}$$
product
-1/2
$$- \frac{1}{2}$$
=
-1/2
$$- \frac{1}{2}$$
-1/2