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Derivative of 0,5-cos(cos(y)+2)

Function f() - derivative -N order at the point
v

The graph:

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Piecewise:

The solution

You have entered [src]
1/2 - cos(cos(y) + 2)
$$\frac{1}{2} - \cos{\left(\cos{\left(y \right)} + 2 \right)}$$
1/2 - cos(cos(y) + 2)
Detail solution
  1. Differentiate term by term:

    1. The derivative of the constant is zero.

    2. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let .

      2. The derivative of cosine is negative sine:

      3. Then, apply the chain rule. Multiply by :

        1. Differentiate term by term:

          1. The derivative of cosine is negative sine:

          2. The derivative of the constant is zero.

          The result is:

        The result of the chain rule is:

      So, the result is:

    The result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
-sin(y)*sin(cos(y) + 2)
$$- \sin{\left(y \right)} \sin{\left(\cos{\left(y \right)} + 2 \right)}$$
The second derivative [src]
   2                                            
sin (y)*cos(2 + cos(y)) - cos(y)*sin(2 + cos(y))
$$\sin^{2}{\left(y \right)} \cos{\left(\cos{\left(y \right)} + 2 \right)} - \sin{\left(\cos{\left(y \right)} + 2 \right)} \cos{\left(y \right)}$$
The third derivative [src]
/   2                                                                \       
\sin (y)*sin(2 + cos(y)) + 3*cos(y)*cos(2 + cos(y)) + sin(2 + cos(y))/*sin(y)
$$\left(\sin^{2}{\left(y \right)} \sin{\left(\cos{\left(y \right)} + 2 \right)} + \sin{\left(\cos{\left(y \right)} + 2 \right)} + 3 \cos{\left(y \right)} \cos{\left(\cos{\left(y \right)} + 2 \right)}\right) \sin{\left(y \right)}$$