sin(cos(x))
d --(sin(cos(x))) dx
Let u=cos(x)u = \cos{\left(x \right)}u=cos(x).
The derivative of sine is cosine:
Then, apply the chain rule. Multiply by ddxcos(x)\frac{d}{d x} \cos{\left(x \right)}dxdcos(x):
The derivative of cosine is negative sine:
The result of the chain rule is:
The answer is:
-cos(cos(x))*sin(x)
/ 2 \ -\sin (x)*sin(cos(x)) + cos(x)*cos(cos(x))/
/ 2 \ \sin (x)*cos(cos(x)) - 3*cos(x)*sin(cos(x)) + cos(cos(x))/*sin(x)